hz6
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				| @ -41,6 +41,17 @@ Node* parse_knowledge_base(char lines[][MAX_LINE_LENGTH], int *index, int line_c | ||||
|     return node; | ||||
| } | ||||
| 
 | ||||
| int is_valid_tree(Node* node) { | ||||
|     if (!node) return 0; | ||||
|     if ((!node->yes && node->no) || (node->yes && !node->no)) { | ||||
|         return 0; // Некорректное состояние: одна ветка отсутствует
 | ||||
|     } | ||||
|     if (!node->yes && !node->no) { | ||||
|         return 1; // Листовой узел
 | ||||
|     } | ||||
|     return is_valid_tree(node->yes) && is_valid_tree(node->no); | ||||
| } | ||||
| 
 | ||||
| int count_products(Node *node) { | ||||
|     if (!node) return 0; | ||||
|     if (!node->yes && !node->no) return 1; | ||||
| @ -110,8 +121,11 @@ int main() { | ||||
|     int index = 0; | ||||
|     Node *root = parse_knowledge_base(lines, &index, line_count); | ||||
| 
 | ||||
|     if (!root) { | ||||
|         return 1; | ||||
|     if (!root || !is_valid_tree(root)) { | ||||
|         printf("Expert z bufetu to vie.\n"); | ||||
|         printf("Chybna databaza\n"); | ||||
|         free_tree(root); | ||||
|         return 0; | ||||
|     } | ||||
| 
 | ||||
|     printf("Expert z bufetu to vie.\n"); | ||||
|  | ||||
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