170 lines
4.9 KiB
C
170 lines
4.9 KiB
C
#include <stdlib.h>
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#include <stdbool.h>
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#include <stdio.h>
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#include <ctype.h>
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#include <string.h>
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#include <math.h>
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#define SIZE 128
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#define TEMPBUFFERSIZE 32
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//kontrola, ze ci vycitane informacie su aritmeticky spravne
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//VRACIA: int: -1 (CHYBA), 0 (False), 1 (True)
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float IsArithCorrect(float num1, float num2, char op, float result)
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{
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float calcResult = 0;
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if (op == '/' && num2 == 0) { return 0;}
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switch (op)
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{
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case '-':
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calcResult = num1 - num2;
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break;
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case '+':
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calcResult = num1 + num2;
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break;
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case '*':
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calcResult = num1 * num2;
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break;
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case '/':
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calcResult = num1 / num2;
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break;
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}
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calcResult = roundf(calcResult* 100.0f) / 100.0f;
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result = roundf(result * 100.0f) / 100.0f;
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if (calcResult == result)
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{
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return 1;
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}
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return 0;
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}
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int main()
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{
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//pomocne premeny
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char line[SIZE], strBuffer[SIZE];
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line[0] = '\0';
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char* strtofEndPtr;
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int LinesOnInputCount = 0;
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while (fgets(line, SIZE, stdin) != NULL)
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{
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if (line[0] == '\n' || line[0] == '\0')
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{
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break;
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}
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strBuffer[0] = '\0';
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sscanf(line, "%127[^\n]", strBuffer);
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if (strBuffer[0] == '\0')
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{
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printf("CHYBA\n");
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continue;
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}
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bool isLineInvalid = false;
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//docasne 'char' premeny
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char num1Temp[TEMPBUFFERSIZE], num2Temp[TEMPBUFFERSIZE], resultTemp[TEMPBUFFERSIZE];
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num1Temp[0] = '\0';
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num2Temp[0] = '\0';
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resultTemp[0] = '\0';
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bool foundEqualSign = false;
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char op1 = 'N'; //N = 'None/NIC'
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for (int i = 0; strBuffer[i] != '\0'; i++)
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{
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bool isNegativeSign = false;
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if (isspace(strBuffer[i]) != 0)
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{
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continue;
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}
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if (strBuffer[i] == '-')
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{
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//kontrola - zistenie, ze ci znak '-' symbolizuje zapornu hodnotu (-456) alebo arit. operaciu minus
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//zistujeme to na zaklade toho, kde sme v riadku (ak sme na zaciatku num1, num2 alebo vyslednehoCisla, tak sa jedna o minusove znamienko)
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if (op1 == 'N' && strlen(num1Temp) == 0)
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{
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isNegativeSign = true;
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}
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else if (op1 != 'N' && !foundEqualSign && strlen(num2Temp) == 0)
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{
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isNegativeSign = true;
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}
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else if (foundEqualSign && strlen(resultTemp) == 0)
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{
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isNegativeSign = true;
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}
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}
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if (isdigit(strBuffer[i]) != 0 || strBuffer[i] == '.' || isNegativeSign)
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{
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//cislo sa bude zapisovat podla toho, kde sme pri citani riadku...
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//ak nenasiel ani arit. znamienko = cislo patri ku prvemu operandu (num1)
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//ak nasiel arit. znamienko ale NIE este symbol '=', tak cislo patri ku druhemu operandu (num2)
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//inak ak ma vsetko, tak zvysne nacitane cisla z riadku mozu byt vyluc. metodou len sucastou vysledku
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if (op1 == 'N')
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{
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strncat(num1Temp, &strBuffer[i], 1);
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}
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else if (!foundEqualSign)
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{
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strncat(num2Temp, &strBuffer[i], 1);
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}
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else
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{
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strncat(resultTemp, &strBuffer[i], 1);
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}
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}
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else if (strBuffer[i] == '=')
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{
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foundEqualSign = true;
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continue;
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}
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else if (strBuffer[i] == '+' || strBuffer[i] == '-' || strBuffer[i] == '/' || strBuffer[i] == '*')
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{
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//predbezna kontrola, ak uz operator mame tak vyhod chybu pri druhom pokuse o nacitanie
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//taktiez, ak sa nasiel minusovy znak tu tak to moze byt len arit. znamienko
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if (op1 != 'N')
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{
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isLineInvalid = true;
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}
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op1 = strBuffer[i];
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}
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else
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{
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isLineInvalid = true;
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break;
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}
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}
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float num1 = strtof(num1Temp, &strtofEndPtr);
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float num2 = strtof(num2Temp, &strtofEndPtr);
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float resultNum = strtof(resultTemp, &strtofEndPtr);
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//** konecna faza = vypisovanie vysledkov
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//ak systematicka chyba
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if (isLineInvalid || op1 == 'N' || IsArithCorrect(num1, num2, op1, resultNum) == -1)
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{
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printf("CHYBA\n");
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}
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else if (IsArithCorrect(num1, num2, op1, resultNum) == 0)
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{
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printf("ZLE\n");
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}
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else
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{
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printf("OK\n");
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}
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}
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return 0;
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}
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